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About Digital Art / Hobbyist Member HexaditidomMale/United States Groups :icondiscomfortzone: DiscomfortZone
 
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Hexaditidom

Artist | Hobbyist | Digital Art
United States

But God shows his love for us in that while we were still sinners, Christ died for us. Romans 5:8

"Everything that needs to be said has already been said. But since no one was listening, everything must be said again." André Gide
We made it all the way to round 20 of our art challenge group, and it may be the final one! Like the very first round, the task is to make a comic. If you've been hesitating to try a round, or haven't in a while, I encourage you to sign up over there. discomfortzone.deviantart.com/…

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:iconziblink:
Ziblink 3 days ago  Hobbyist Photographer
Point: most square roots are irrational numbers.

Point I can get rational numbers by squaring irrational numbers like root(2)+root(8)

Question, do you know with your stupendous math knowledge, whether anyone knows if all irrational numbers will eventually become rational if squared an arbitrary number of times? It's really starting to bug me.
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:iconhexaditidom:
Hexaditidom 3 days ago  Hobbyist Digital Artist
So apparently my shout section is now math time! I am okay with this.

I would say no to irrational numbers in general. In fact, not just for iterations of squaring but any power n, by definition the only solutions r to rn = a/b where a,b are integers, are roots r of the polynomial rn - a/b, or brn - a. These will be algebraic numbers which covers many irrationals but excludes transcendentals. (The first picture on that page is my current desktop!)
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:iconziblink:
Ziblink 3 days ago  Hobbyist Photographer
*Snaps fingers* transcendentals! *That's* what I forgot! It makes perfect sense if you include them in there's no possible way to match enough of them to integers! I am almost disappointed I didn't think of that. (On the other hand I just had to spend 5 minutes trying to recall how you convert roots into powers, so I may be getting rusty...)
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:iconmidday-mew:
Midday-Mew Mar 23, 2014   General Artist
g(161/255) = 204/255 = .8

g(1.00) = 1.00

g(x) → 1.00
as
x → 1.00

0 ≤ x ≤ 1.00

g(0) ≤ g(x) ≤ 1.00

0 < g(0)

What equation is g(x), or is there not enough information?

What I do know is that when
0 ≤ x < 1
is true, then
g(x) > x

However, when
g(x) = x
is true, then
x = 1

These numbers are for the brightening of a color in Photoshop towards a pure hue and apply to both Saturation and Value, measured in a range from 0 percent to 100 percent for Saturation and the same range for Value, but the amount brightened depends on the initial color, which after being brightened yields the final color. The amount brightened can vary for different values of Value and Saturation, but are consistent with an unknown formula that turns a value of 100 percent to 100 percent, 0 percent to a number higher than 0 percent but less than 100 percent, and 161/255 (approximately 63 percent) to exactly 80 percent.
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:iconhexaditidom:
Hexaditidom Mar 23, 2014  Hobbyist Digital Artist

Well, there's not enough to know exactly how the function works. It could be linear (in red) or it could follow some kind of curve. What's this for?
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:iconmidday-mew:
Midday-Mew Mar 24, 2014   General Artist
I don't think it's a curve, TBH. If it is a curve, it'd probably be x^2. I think it's linear, though. But with a formula, I can test the numbers and see if they work.

Also, PageWizard solved the same question (I asked him too), and you can see what he wrote here: comments.deviantart.com/4/1770…
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:iconwingedozelot:

Hi there :D I'm here on behalf of :iconworldwide-war:, an upstarting OCT.

If you're up to the challenge of an intergalactic tournament, we hereby invite you to join us in thrilling clashes between competitors of any species from all over the universe!

See you around~ :D

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:iconseodrawscartoons:
SEODrawsCartoons Sep 1, 2013  Student Digital Artist
Hello there. Sociable plz 
I've been checking around in your gallery
and you have some pretty neat stuff here. ;)
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:iconhexaditidom:
Hexaditidom Sep 1, 2013  Hobbyist Digital Artist
Why thanks! :D
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:iconseodrawscartoons:
SEODrawsCartoons Sep 1, 2013  Student Digital Artist
You're welcome! ;)
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